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How many moles of glucose (C6H12O6) are in 5.0 liters of a 2.5 M C6H12O6 solution?
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\[molarity = \frac{moles}{liters}\]so \[2.5M = \frac{moles}{5 L}\]Multiply it out, and you get 5 x 2.5 = 12.5 moles.
So would 13 be acceptable? that is the closest option to 12.5
yeah.
How many grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl? Show all of the work needed to solve this problem. Mg (s) + 2 HCl (aq) yields MgCl2 (aq) + H2 (g)
4.8 liters x 5.0 M = 24 moles of HCl For 2 moles of HCl, 1 mole of Mg is used. So we need 12 moles of Mg, which is 12 x 24.31 = 291.72 grams of Mg
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