Question

DId I answer this correctly?

Answer 1

Hold on have to write the equation...

Answer 2

expression*

Answer 3

\[6x ^{2} + x - 12d/3x ^{2} + 14x - 24\]

Answer 4

6x2 + x - 12 ---> (2x + 3)(3x - 4) (cross out 3x - 4) ----> 2x + 3
______________ _________________ _________
3x2 + 14x - 24 ----> (x + 3)(3x - 4) (cross out 3x -4) ----> x + 3

x ≠ -3

Answer 5

\[\frac{6x^2+x-12}{3x^2+14x-24} ?\]

Answer 6

yea :P I don't know how to do that... :P

Answer 7

It is okay. Let me check your work...

Answer 8

I have to Simplify the expression and identify the restrictions

Answer 9

The bottom factorization does not seem to be correct!
However your top is awesome! :)

Answer 10

You do know that 3(-4) is not -24 right?

Answer 11

Oh sorry! I made a mistake, the bottom should be (3x -4)(x + 6)

Answer 12

Yes :P

Answer 13

Perfect factorization :)

Answer 14

So we have
\[\frac{(2x+3)(3x-4)}{(3x-4)(x+6)}\]

Answer 15

Now you cancel something assuming x doesn't equal what number?

Answer 16

well I canceled out 3x -4 on the top and 3x - 4 on the bottom

Answer 17

right assuming 3x-4 does not equal 0
or 3x does not equal 4
or x does not equal 4/3
:)

Answer 18

Ohh right! I forgot about those two!

Answer 19

So yeah we would have
\[\frac{2x+3}{x+6} , x \neq \frac{4}{3}\]

Answer 20

Great job @LifeIsADangerousGame

Answer 21

Thanks!