Question

As a box is pushed 30 meters across a horizontal floor by a constant horizontal force of 25 newtons, the kinetic energy of the box increases by 300 joules. How much total internal energy is produced during this process?

Answer 1

The work done is the sum of the change kinetic energy and the change in internal energy.\[W = \Delta K + \Delta Q\]Work is the dot product of applied force and displacement.\[\vec F\cdot \Delta \vec x = \Delta K + \Delta Q \longrightarrow \boxed{\Delta Q =\vec F \cdot \Delta \vec x - \Delta K }\]