Question

Three balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and sides of the cylinder. The diameter of each ball is 13 cm.
a. What is the volume of the cylinder rounded to the nearest cubed centimeter?
b. What is the total volume of the three balls rounded to the nearest cubed centimeter ?
c. What percent of the volume of the container is occupied by the three balls?

Answer 1

very good question.. .
f you solve it yourself, you will master volumes. give a try

Answer 2

*if

Answer 3

I've tried giving it multiple tries,trust me.

Answer 4

Geometry is notmy strong suite. Can you help me with this question? This is the only out of ll my my 50 questions I don't understand.

Answer 5

lol.. .i trust you fully... :P

since balls are touching the cylinder boundaries,
cylinder radius r = ball radius = 6.5 cm.
height of cylinder h = 13 x 3 = 39 cm

a. volume of cylinder = pi . r2 x h = pi x 6.5 x 6.5 x 39 = 5176 cm3
b. volume of 3 balls = 3 (4/3 pi x r3) = 4 x pi x 6.5 x 6.5 x 6.5 = 3451 cm3
c. can you calculate ?

Answer 6

c) bope!

Answer 7

nope* or spell apparently lol

Answer 8

ok..
c. we need to find how much percent is balls volume inside cylinder
so just take (3451/5176) x 100 = 66.66 %

Enjoy..

Answer 9

Thank you!