Question

What is the simplified radical form of this exponent:

7^-(2/3)

Answer 1

\(\frac{1}{\sqrt[3]{7^2}}\)

Answer 2

your exponent is \(-\frac{2}{3}\) which has
1) a numerator 2
2) a denominator 3
3) a minus sign

they mean
1) square
2) take the cubed root
3) take the reciprocal (flip it)

Answer 3

can you should me how that would go? @satellite73

Answer 4

you mean as a number? you need a calculator for this one

Answer 5

Would it just be:\[1 \over \sqrt[3]{49}\]

Answer 6

if you had
\[8^{-\frac{2}{3}}\] we could say
1) cube root of 8 is 2
2) 2 squared is 4
3) the reciprocal of 4 is \(\frac{1}{4}\) so
\[8^{-\frac{2}{3}}=\frac{1}{4}\]

Answer 7

yes, you could write
\[\frac{1}{\sqrt[3]{49}}\]

Answer 8

but isn't it that you can't have a square root in the denominator?

Answer 9

@satellite73