2.Write the equation of the line which passes through (2, 1) and is perpendicular to x = –2. (1 point)

Question

anonymous · Answer

Help

anonymous · Answer

the equation of a line passing through a pont(x1,y1)
and having slope m is
(y-y1)=m(x-x1)

da_scienceman · Answer

m really trying to knw if the answer is x = -2! No info cos both parallel lines got same gradient. But then a fool might write down y - 5 = m(x + 2) , but then m is the gradient but should be same for both parallel lines. Again, is d gradient of a parallel line nt 0?

anonymous · Answer

Yeah, I got that part but I keep getting, y = 2x -3

da_scienceman · Answer

how did u get d gradient

anonymous · Answer

Is the supposed to be 1/2? as the slope

da_scienceman · Answer

why 1/2? m nt sure if its 1/2 though! its long i dealt with this type of stuff lol

anonymous · Answer

the line given is a vertical line.
so it's slope is infinity..
the line perpendicular to it must have m=0

anonymous · Answer

so here m=0

da_scienceman · Answer

recall that gradient is m = (y1 - y2)/(x1 - x2
)

anonymous · Answer

I think it's 1/2, I'm 90% certain.

anonymous · Answer

y=1?

da_scienceman · Answer

Nope on the contrary, the product of the gradietn of two perpendicular lines is -1!

da_scienceman · Answer

so if d line was L1, andother is L2, then their gradients are related by L1.L2 = -1

anonymous · Answer

Wth I'm confused you guys.

anonymous · Answer

@Katiebae wat's the ans....have u any options?

da_scienceman · Answer

i ll work it out before i get home, challenging!

anonymous · Answer

I'm sorrry but you guys  arent helping

da_scienceman · Answer

r u sure ur question is correct

anonymous · Answer

I think it's y = 1/2x

anonymous · Answer

Yes it's correct^

da_scienceman · Answer

why?

anonymous · Answer

Because the y intercept becomes a zero

anonymous · Answer

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