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Mathematics 7 Online
OpenStudy (anonymous):

please help! tan^{-1}(tan−3π/5)

OpenStudy (anonymous):

\[\tan^{-1} (\tan -3\pi/5)\]

OpenStudy (maheshmeghwal9):

The answer is -3pi/5.

OpenStudy (anonymous):

(-3pi/5)+npi, and n belongs to integer

OpenStudy (maheshmeghwal9):

ya actual answer as @AndrewNJ

OpenStudy (maheshmeghwal9):

wait a minute I give u one thing:)

OpenStudy (anonymous):

thanks andrew & mahesh but where did you get\[ +npi\]from?

OpenStudy (maheshmeghwal9):

becoz tan function has periodicity of pi & it repeats its values after every period of pi.

OpenStudy (anonymous):

u can lok at my attach pic

OpenStudy (maheshmeghwal9):

so the value on -3pi/5 will be equal to -3pi/5+npi for all n belonging to integers

OpenStudy (anonymous):

the graph of tan repeats in a pi so it can have infinity root of a certain value

OpenStudy (maheshmeghwal9):

wait for 2 min.

OpenStudy (anonymous):

i think the next time is three mins:)

OpenStudy (anonymous):

where did u puzzled guy?

OpenStudy (maheshmeghwal9):

OpenStudy (maheshmeghwal9):

It is for ur help @Ren93

OpenStudy (anonymous):

thank you

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