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please help! tan^{-1}(tan−3π/5)
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\[\tan^{-1} (\tan -3\pi/5)\]
The answer is -3pi/5.
(-3pi/5)+npi, and n belongs to integer
ya actual answer as @AndrewNJ
wait a minute I give u one thing:)
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thanks andrew & mahesh but where did you get\[ +npi\]from?
becoz tan function has periodicity of pi & it repeats its values after every period of pi.
u can lok at my attach pic
so the value on -3pi/5 will be equal to -3pi/5+npi for all n belonging to integers
the graph of tan repeats in a pi so it can have infinity root of a certain value
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wait for 2 min.
i think the next time is three mins:)
where did u puzzled guy?
It is for ur help @Ren93
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thank you
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