The Pythagorean Theorem shows the relationship between the sides of a right triangle and the hypotenuse. The formula for the Pythagorean Theorem is a2 + b2 = c2, where a and b are the sides and c is the hypotenuse. A. Write a polynomial expression for c2. (
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http://pavcs.blackboard.com/bbcswebdav/pid-695363-dt-content-rid-956496_2/xid-956496_2 Question #9
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(x+3)^2+(x+2)^2=c^2 can u simplify?
im not sure ,
Give it a try, and ask any questions that come up.
okay ,
i dont get it .
"I don't get it" isn't a question.
how do you simplifiy it from (x+3)^2 +(x+2)^2 = c^2 ?
using this form (a+b)^2=a^2+b^2+2ab expand (x+3)^2 and (x+2)^2. Then add the like terms to simplify. see if u can do nw.
im sorry , but i just cant understand this.
\[(a+b)^2=a^2+2ab+b^2\] in \[(x+3)^2\] u hav a=x and b=3 applying this in \[a^2+2ab+b^2\] u get \[x^2+2*x*3+3^2\] \[=x^2+6x+9\] similarly can u do for \[(x+2)^2\]?
yes.
vat do u get for that dr?
idk .
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