(sqrt)- 6(2 + (sqrt) - 6))
\[\sqrt{-6}\left( 2 +\sqrt{-8} \right)\]
What format is the answer supposed to be in? Does it want a decimal, or fraction, or what?
just solve
No instructions at all? Cause if you just solve it'll come out to be one lonnnnnnggggg decimal.
But if you keep it in square root form it'll be cleaner. It just depends on what your teacher is looking for.
-4(sqrt) 3 + 21(sqrt)6 is one of the answers
choices*
Okay so it wants it just like that alright. Well you have your equation. \[\sqrt{-6}(2+\sqrt{-8})\] You need to multiply everything by \[\sqrt{-6}\] So it'll look like this,\[(\sqrt{-6}\times2)+(\sqrt{-6}\times \sqrt{-8})\]
Can you take it one step further from there?
no
Alright well \[2\times \sqrt{-6}\] can't be simplified any further. So you have 1/2 of your answer.
Now for the second part of your answer,\[\sqrt{-6} \times \sqrt{-8}\] To multiply square roots you multiply the numbers within their sign. soooo\[\sqrt{-6(-8)}\] Now you solve that part.
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