Question

Simplify the expression.
x sqrt 8x^3 + sqrt2 + 4 sqrt2x
If the simplified expression is written in standard form, what is the leading coefficient?

PLEASE ANSWER WITH A NUMERICAL ANSWER

Answer 1

Is this the question?\[x \sqrt {8x^3} + \sqrt2 + 4 \sqrt{2x}\]

Answer 2

oops, no.
It's x sqrt8x ^3 + xsqrt2+4sqrt2x

Answer 3

I still can't tell where to start. Can you use the equation editor to help make it clear?

Answer 4

Is this it?
\[x \sqrt {8x^3} + \sqrt2x + 4 \sqrt{2x}\]

Answer 5

\[x \sqrt{8x^3} + x \sqrt{2} + 4\sqrt{2x}\]

Answer 6

Good. Here we go.\[x \sqrt {8x^3} + \sqrt2 x+ 4 \sqrt{2x}=2x^2\sqrt{2x}+\sqrt2x+4\sqrt{2x}\]

Answer 7

The leading term in standard form is the first one (power of x is 5/2). The coefficient of that term is 2sqrt2, approximately 2.82

Answer 8

Maybe one more step will make this clearer....\[2x^2\sqrt{2x}+ x \sqrt2 + 4 \sqrt{2x}=2\sqrt2x^2 \sqrt x+ x \sqrt2 + 4 \sqrt x\]