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Mathematics 22 Online
OpenStudy (anonymous):

I need help with this question...

OpenStudy (anonymous):

OpenStudy (anonymous):

solving for y would make this problem more simple than it is right now

OpenStudy (anonymous):

Yes, but how? Can you do it out for me?

OpenStudy (anonymous):

@Outkast3r09

OpenStudy (anonymous):

alright so since you are graphing you probably know how to solve equations for x am i right?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

alright so basically you want each equation to be in the form of y=f(x) where f(x) is any function with the variable x. for the second equation, simply add y to both sides, and then subtract 4 from both sides to get y=f(x)

OpenStudy (anonymous):

Mmk..following you so far

OpenStudy (anonymous):

once you have them both in y=f(x), you'll have them in point-intercept form: y=mx+b, where m is your slope, and b is your y intercept (when your line crosses the y-axis

OpenStudy (anonymous):

slope=m=rise/run, correct? so using your y intercept make your first point and then use rise of run to find your next point. for example your second equation looks like this y=4x-4 this means that at y=-4, x=0 so graphing this you get |dw:1339786790105:dw|

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

now m=4 correct which is the same as 4/1 meaning rise = 4 and run = 1 ... so move up 4 and right 1

OpenStudy (anonymous):

so the answer is whichever graph has those two points?

OpenStudy (anonymous):

|dw:1339786906955:dw|

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