I need help with this question...
solving for y would make this problem more simple than it is right now
Yes, but how? Can you do it out for me?
@Outkast3r09
alright so since you are graphing you probably know how to solve equations for x am i right?
yea
alright so basically you want each equation to be in the form of y=f(x) where f(x) is any function with the variable x. for the second equation, simply add y to both sides, and then subtract 4 from both sides to get y=f(x)
Mmk..following you so far
once you have them both in y=f(x), you'll have them in point-intercept form: y=mx+b, where m is your slope, and b is your y intercept (when your line crosses the y-axis
slope=m=rise/run, correct? so using your y intercept make your first point and then use rise of run to find your next point. for example your second equation looks like this y=4x-4 this means that at y=-4, x=0 so graphing this you get |dw:1339786790105:dw|
yea
now m=4 correct which is the same as 4/1 meaning rise = 4 and run = 1 ... so move up 4 and right 1
so the answer is whichever graph has those two points?
|dw:1339786906955:dw|
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