Question

Please help! Limit? Click to view

Answer 1

\[\lim_{n \rightarrow \infty}2n^2/n^2-2\]

Answer 2

Just take \[n^2\] common from denominator,

\[\lim_{n \rightarrow \infty} 2n^2/n^2(1-2/n^2)\]

Cancel whatver is being cancelled and then put the limit,

\[\lim_{n \rightarrow \infty} 2/(1 - 2/n^2)\]

Put the limit, Remember one thing:\[x/\infty = 0\]

\[2/(1 - 2/\infty^2)\]
\[2/(1 - 0)\]

= 2 is the answer...

Answer 3

Oh I see. Thanks!

Answer 4

Welcome dear...