Question

Last problem! Please help! Click to view

Answer 1

\[\sum_{k=1}^{4}(k-1)^k\]

Answer 2

Sum?

Answer 3

Hmm... Your best bet is summing it manually.

Answer 4

ya just do it like small kids, put the valu of k in the four terms

Answer 5

There is a solution via manipulations, but it requires knowledge of certain notation that I don't know if you're aware of. Once you figure out the solution, I can post the result in this notation if you like.

Answer 6

Dang. You're typing alot.

Answer 7

Whoa. What happened?

Answer 8

@Limitless?

Answer 9

Oh, I was just idly working on the solution generally. I am waiting for you to find the answer to your specific case.

Answer 10

I am coming to the conclusion there is not a general form solution.

Use manual summation.

Answer 11

@FoolForMath, is there a closed form for
\[\sum_k k^{k+1}[0 \le k \le n-1]?\]

Answer 12

I have not made any progress other than observing it's equivalent to
\[\sum_{j,k}k[0\le j \le k \le n-1].\]