A truck with a mass of 3000kg is accelerated uniformly from rest to 6m/s1 over a distance of 600m up an incline of 1:30. The resistance against motion is 200N. Calculate the component of gravitational force parallel to the plane. Please show your calculations.

Question

anonymous · Answer

if you had the angle of the incline, cant you use 29400 x sin.angle?

anonymous · Answer

3000 x 9.8 = 29400N

ujjwal · Answer

|dw:1339839047892:dw| The gravitational force parallel to plane will always be equal to mg$\sin \theta$.
where  $\theta$ is the angle of inclination.