Question

I got this question wrong on my homework.. Can anyone show me step by step how to do this please?
(-2x^2/5)^2

Answer 1

\[\left(\frac{-2x^2}{5}\right)^2\]
\[=\frac{\left(-2x^2\right)^2}{5^2}\]

Answer 2

\[\left( \frac{-2x^2}{5}\right)^2=\frac{-2x^2}{5} \cdot \frac{-2x^2}{5}\]
and then..?

Answer 3

\[=\left(\frac{(-2\times-2)(x^2\times x^2)}{5\times 5 }\right)\]

Answer 4

@UnkleRhaukus \[4x ^{4}/ 25\] ?

Answer 5

right.

Answer 6

Yup.

Answer 7

@UnkleRhaukus So when you have the exponent on the outside is it adding the exponents or multiplying ?

Answer 8

Multiplying.
\[(a^b)^c=a^{bc}\]

Answer 9

\[(x^n)^m=x^{n\times m}=x^{nm}\]

Answer 10

WOOOOOOO! Ok thanks boys for all your help! :) Love it! @Limitless @UnkleRhaukus

Answer 11

You're welcome.

Answer 12

@Limitless @UnkleRhaukus So if I have \[(4z ^{3}/3)^{2}\] would it be \[16z ^{6}/6\]

Answer 13

not quite

Answer 14

I mean over 9 not 6

Answer 15

Yup.

Answer 16

that is it

Answer 17

I forgot to do 3x3 I did 2x3

Answer 18

lol It confuses me!!!! :(

Answer 19

It just takes practice, that is all.

Answer 20

Thanks for your help sweetheart @Limitless

Answer 21

No problem. Teaching people is fun if they want to learn.