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Mathematics 18 Online
OpenStudy (anonymous):

can some one teel me how to work out probability e.g. a clothing scenario... 3 hats, 5 shirts, 8 pants, 6 socks, and 4 shoes. how many different outfits? Please show working!!!

Parth (parthkohli):

It's simply 3 * 5 * 8 * 6 * 4

Parth (parthkohli):

Let's take an example of 2 shoes and 2 socks, we have 2 shoes for every 2 socks.

Parth (parthkohli):

So we multiply.

OpenStudy (anonymous):

is there a scenario where it might not use this method?

Parth (parthkohli):

There are some questions that are changed so that the question is made difficult. let me think.

Parth (parthkohli):

They manipulate the questions sometimes.

Parth (parthkohli):

Like if you have five letters A,B,C,D,A.. how many different ways can you fill it in?

Parth (parthkohli):

We'll not have 5 * 4 * 3 * 2 * 1, but we'll have (5 * 4 * 3 * 2 * 1)/2

Parth (parthkohli):

Because the letters are repeating, get it?

OpenStudy (anonymous):

not really, sorry DX

Parth (parthkohli):

And now think if you have five letters A,A,A,B and C. The number of ways you can fill them in is 5!/3!

Parth (parthkohli):

When something repeats, then we have (number of letters)! over (number of times the letter repeats)!

Parth (parthkohli):

! means factorial.

OpenStudy (anonymous):

yes ok i see what you are geting at!!

Parth (parthkohli):

Why do we divide? Think of letters A,A,A,B,C.. now let's name the 3 A's First is A1. Second is A2. Third is A3.

Parth (parthkohli):

If we have something like this - A1, A2, A3, B, C and then this - A2, A1, A3, B, C Of course they aren't any different, because A1, A2 and A3 are just damn A's!

OpenStudy (anonymous):

haha i get what you mean XD

Parth (parthkohli):

Exactly xP

Parth (parthkohli):

So we divide the number of ways the 3 A's can be arranged, which is just 3 factorial :P

OpenStudy (anonymous):

so if the A's did matter then it would just be 5!

Parth (parthkohli):

Yep you got it!

OpenStudy (anonymous):

ok thanks a lot XD

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