Openstudy user L's medal count is 112 less than the medal count of OpenStudy user P. OpenStudy user P's accuracy (medals received-over-questions answered) is 79.85%. OpenStudy user L's accuracy is 62.41%
who has answered more questions?
can someone tell me how to express this in algebra??
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Parth (parthkohli):
lol P is me
OpenStudy (lgbasallote):
hey
OpenStudy (lgbasallote):
lol you sent faster than me
Parth (parthkohli):
You have answered more xP
OpenStudy (lgbasallote):
and no it aint you..feeler :p
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OpenStudy (lgbasallote):
so how to express this algebraically @ParthKohli ?
Parth (parthkohli):
Your accuracy is less. I think it has to do something with inverse relation.
Parth (parthkohli):
The lesser the accuracy, the more questions answered.
OpenStudy (lgbasallote):
lol..is that a legit logic o.O
Parth (parthkohli):
Yeah
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OpenStudy (lgbasallote):
well my book requires a more legit solution :p
Parth (parthkohli):
I compared the medal count and I have exactly 112 more :P
OpenStudy (lgbasallote):
hah lol
OpenStudy (lgbasallote):
proves nothing
OpenStudy (kropot72):
Let P's medal count = x
L's medal count = x - 112
P's number of questions = x/0.7985
L's number of questions = (x - 112)/0.6241 = (x/0.6241) -179
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