Question

6.Create your own third degree polynomial that when divided by x + 2 has a remainder of –4.

Answer 1

x^3 + x^2 -2x - 4 = 0

Answer 2

i used the remainder theorem f(-2) = -4

Answer 3

1x^2-1x – 4/x+2 <<<<< is the answer

Answer 4

plug -2 into this gives
(-2)^2 + 2 +2 + 2 = 6
that a remainder 6 not -4

Answer 5

if a polynomial is divided by (x+2) and the remainder is -4, then
if you plug x = -2 into the polynomial then value of polynomial will be -4

Answer 6

i still dnt understand

Answer 7

ok lets suppose we divide x^2 - 4x + 1 by x - 1:

x - 3
-------------
x - 1) x^2 - 4x + 1
x^2 - x
--------
-3x + 1
-3x + 3
-------
-2

remainder is -2

now replace x in polynomial by 1 ( the 1 fro x-1) we will get -2

(1)^2 - 4(1) + 1 = 1 - 4 _ 1 = -2

Answer 8

perhaps you haven't come across the remainder theorem before sassy?

Answer 9

try P(x) = (x+2)^2 -4