Question

A furniture shop refinishes chairs. Employees use one of two methods to refinish each chair. method one takes 0.5 hours and the material costs $10. method two takes 1.5 hours and the material costs $5. next week they plan to spend 53 hours in labor and $560 dollars in material for refurnishing chairs. How many chairs should they plan to refinish with each method?

Answer 1

Let x = number of chairs using method 1
Let y = number of chairs using method 2

Then:
53 = 0.5x + 1.5y
560 = 10x + 5y

I assume that you know how to solve this system of equations for x and y. You should end up with making 46 chairs using method 1 and 20 chairs using method 2...for a total of 66 chairs.

Answer 2

okay
method uno:
Our factors are .5 hours $10 = 53 hours and 560 dollars
so
.5 ÷ 53= ? and $560 ÷ $10= ?

method dos:
Our factors are:
1.5 hours $5 = 53 hours and $560
so
1.5 ÷ 53 = ? and $560 ÷ $5 =?

Answer 3

@rebeccaskell94: based on his previous question, the questions are really asking what number of chairs should be made using each method to make the most number of chairs.

Answer 4

How many chairs should they plan to refinish with each method?<--- oh yeah that xD oops

Answer 5

Shane Wins..You Redeemed yourself. Thanks Alot

Answer 6

No problem...I did the same thing rebecca did the first time...the question should be worded slightly better :)

Answer 7

Agreed lol

Answer 8

Blame Algebra lab.. yall have a good night. thanks again