Question

An arm is rotating at a rate of 160 deg/s and accelerates at a rate of 1000deg/s^2 for a time of .2 seconds. What change in angular displacement occurs during this time?

Answer 1

the position function is:
\[\frac{1}{2}a t^{2} + v_{0} t\]
a - acceleration
v - initial velocity
plug in .2 for t

Answer 2

so the angular displacement is the position when t=.2

Answer 3

what do you get when you plug in the numbers?

Answer 4

160 x .2 + 1/2 x 1000 x 0.2
32 + 100
132
correct?

Answer 5

not quite...you need to square the .2 where it has t^2

Answer 6

oh yes, great. thanks for your help.