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Physics 9 Online
OpenStudy (ujjwal):

I always took components of vectors to be vectors. But now my book says "component of vectors are not vectors. They are scalars." My understanding: They have both direction and magnitude and on vector addition they give the original vector and yet my book says they are scalars. Can anyone explain how?

OpenStudy (maheshmeghwal9):

they are originally vectors. a scalar addition can't give a vector. so book may be wrong @ this point.

OpenStudy (ujjwal):

The text book which says so is "University Physics with Modern physics, 12th edition" by HUGH D. YOUNG ROGER A. FREEDMAN One thing which gives me a hint that they might be scalars is that components are essentially projections! which might give a conclusion that they are scalars! But then i am not sure.

OpenStudy (maheshmeghwal9):

ya I agree that they are projections. but they are basically vectors. & I also have that book. yet there are some exceptional cases such as components of vectors, they are basically vectors which gives out a vector but can be also termed as scalar becoz they are only projections on x-axis & does not have any matter about real world. we use them as they are the solutions of many questions in physics. but we can't give them a title of their real existence as a vector exists. so as a summary, they are vectors. becoz the majority of all physics book says they are vectors.

OpenStudy (ujjwal):

@maheshmeghwal9 so, your conclusion is that they are vectors because majority of physics textbook says they are vectors..

OpenStudy (maheshmeghwal9):

ya absolutely.

OpenStudy (maheshmeghwal9):

by the way on which page no. this quotation is written in HD Young?

OpenStudy (ujjwal):

There was a time when every single human on earth said earth is flat.

OpenStudy (ujjwal):

Page-36

OpenStudy (maheshmeghwal9):

k! wait for 2 min.

OpenStudy (maheshmeghwal9):

So this is what u are saying about?

OpenStudy (maheshmeghwal9):

?

OpenStudy (ujjwal):

yep. The part in the caution.

OpenStudy (maheshmeghwal9):

k! think on that:) If we walk through the book according to that caution.k! then it is that thing which I was saying earlier that they are only projections. so termed as scalar they does not have right to matter with real world as a vector has that right. but how can u calculate a vector with 2 scalars? can u tell me? It is impossible. so u must take the summary as they are "scalar vectors" which r unreal but play an important role in calculating vectors.

OpenStudy (maheshmeghwal9):

sorry but I can say only this much:)

OpenStudy (maheshmeghwal9):

If u have doubt in my reply then ask me:)

OpenStudy (maheshmeghwal9):

Even the book is saying that they are component vectors. but termed as scalar for representation:) u see the attachment carefully.

OpenStudy (maheshmeghwal9):

now I think u must gt it:)

OpenStudy (anonymous):

It's kinnnnda both. They're scalars if you know what direction they're pointing in. :P So, if I ask you, what is the x-component of this vector, you could tell me the magnitude of the x-component or the magnitude and direction...but either way there would be no ambiguity since you know what direction was going to be before you got the answer. It's a little more subtle though than magnitude, since this scalar can be negative to indicate pointing in the opposite direction from the corresponding unit vector.

OpenStudy (unklerhaukus):

A point in three dimension can be represented \[P(x_1, x_1, x_3)=x_1\cdot\hat {\bf{i}}+x_2\cdot\hat {\bf j} +x_3\cdot\hat {\bf k}\] \(\{x_1, x_1, x_3\cdots \}\) are the component vectors, which have no direction only magnitude \(\{\hat {\bf i}, \hat {\bf j}, \hat{ \bf {k}}\}\) are the unit vectors in the three basis dimensions these provide the direction

OpenStudy (anonymous):

Again, it's important to note that they have more than just magnitude, they have signed magnitude. It's also okay to represent them as \(\{x_1 \hat \imath,\ x_2 \hat \jmath,\ x_3 \hat k\}\).

OpenStudy (ujjwal):

@yakeyglee what do you mean when you say "signed magnitude"?

OpenStudy (anonymous):

For instance, the vector \(\vec v = 6 \hat \imath - 2 \hat \jmath + 3 \hat k\) has components \(( 6 \hat \imath, - 2 \hat \jmath, 3 \hat k )\). If we were to omit the directions, we would be correct in saying \((6,-2,3)\), however incorrect in simply stating the magnitudes \((6,2,3)\), as that describes a different vector.

OpenStudy (anonymous):

They're signed in concordance with their direction with respect to the corresponding unit vectors.

OpenStudy (ujjwal):

So, sign plays an important role here. Even if direction is omitted in case of component vector we should not change the sign which were originally assigned to them. Do i get it right?

OpenStudy (anonymous):

Exactly.

OpenStudy (ujjwal):

thanks @UnkleRhaukus and @yakeyglee ...

OpenStudy (vincent-lyon.fr):

I entirely agree with @yakeyglee about the signed scalar. Actually, I do not think it is no important debate whether vector components are vectors or signed-scalars. It is purely a matter of choice of vocabulary. In France, we use (or we should use) : components = vectors coordinates = scalars (signed of course) But lots of people interchange them. We usually say coordinates for vector displacement.

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