Question

I can't figure out this one for some reason. (Probably missing a step or something.

0=361201-(p+1)^2

Answer 1

First expand the (p+1)^2 like so

(p+1)(p+1)

After that it's arithmetic.

Answer 2

calculator is allowed or you have to figure out the root manually ?

Answer 3

\[0=361201-(p+1)^2\]\[361201-(p^2+2p+1)=0\]\[361201-p^2-2p-1=0\]\[-p^2-2p+361200=0\]\[p^2+2p-361200=0\]\[p=\frac{-2 \pm \sqrt{2^2 - 4(1)(-361200)}}{2(1)}\]\[p=\frac{-2 \pm \sqrt{1444804}}{2(1)}\]\[p=\frac{-2 \pm 1202}{2}\]Can you find the values of p?

Answer 4

why not subtract 361201 from both sides ,,cancel out the -ve sign..take sqrt of both sides..still gives you 2 ans..

Answer 5

I have to find them manually. I thought that I was supposed to use the quadratic equation but it seemed somewhat difficult for me to do so I assumed there must be another way. Guess I'll have to remember to use it

Answer 6

Thanks everyone!

Answer 7

I meant formula, sorry. ^_^

Answer 8

(p+1) ^2 = 361201
\[p+1 = \pm \sqrt{361201}\]

\[p + 1 = \pm 600... ?\]

can you do trial and error few times to get the exact root..

Answer 9

I think it would be best to leave the answer as a root. It's the most accurate.

Answer 10

agree.. but if it is a perfect square.. i would want to compute

Answer 11

sqrt would be 601,,and its not that difficult to know that..as you already know whats 600^2
601^2 = (600+1)^2 or 600^2 + 1201