Question

An Open vessel Kept at 300K was cooled 280K The percentage increase in weight of the vessel is (weight of air=29.2 g/mol)?

Answer 1

The asnwer should be 7

Answer 2

@mathslover

Answer 3

did u get that 1st one ... first reply there @Yahoo!

Answer 4

yup

Answer 5

@quarkine

Answer 6

sorry i dont have much chemistry knowledge

Answer 7

mahesh meghwal is there

Answer 8

mani jha and more

Answer 9

@.Sam.

Answer 10

\[pV=nRT\]

Answer 11

\(T_1= 300K\) \(T_2=280K\)

\(p,V,R,\) are constant

Answer 12

\[pV/R=n_1T_1=n_2T_2\]

Answer 13

\[\frac{T_1}{T_2}=\frac{n_2}{n_1}\]

Answer 14

can you figure it out form here?

Answer 15

let me try!!

Answer 16

@UnkleRhaukus not getting!!

Answer 17

so can you tell me the ratio of mole after to moles before cooling?

Answer 18

1.071

Answer 19

15/14

Answer 20

hmm this dosent seem right i dont think we can use the idea gas las.

Answer 21

i got 6.67% is that the right answer?

Answer 22

@Tushara yes can u plzz show ur work!!

Answer 23

@Tushara plzz help

Answer 24

give me a min :) ill upload my working, just took a foto of it

Answer 25

ok

Answer 26

ive not chem since quite long, so let me know if i did anything wrong

Answer 27

ive not done chem*

Answer 28

thxxxx

Answer 29

np :)