Question

10L of a gas collected over 1000ml of water at 300K after collection weight of the water decreased by 0.24g The vapour pressure of water is?

Answer 1

wht abt me ?

Answer 2

so yahoo ! it is your home work right ?

Answer 3

yup

Answer 4

sorry i forgot u @mathslover

Answer 5

np

Answer 6

Can u help me

Answer 7

@asnaseer

Answer 8

@Tushara

Answer 9

no wat happens..............partial pressure of liquid = partial pressure of gas?

Answer 10

the answer i got is way too small to be right, wat is the answer?

Answer 11

@Tushara the asnwer should be 7

Answer 12

oh ok, sorry, m not getting the right answer, cant help you in dis one

Answer 13

@AravindG

Answer 14

vapour pressure =molecular weight/2

Answer 15

so we need MM

Answer 16

yep try to use the data given

Answer 17

do u hav final answeR?

Answer 18

yup the asnwer should be 7

Answer 19

wait a sec i ,ade a mistake

Answer 20

i think u shud do it this way.............
for water vapour pv=(w/m)rt
u van get v using
p1v2=p2v2 for that gas

Answer 21

vapour density =molecular weight/2

Answer 22

srry i read the qn wrong

Answer 23

seems @A_Avinash_Goutham's working is good

Answer 24

wait u wont get volume that way......u dont have initial pressure :P

Answer 25

@heena

Answer 26

@chmvijay

Answer 27

hey u have to find vapour pressure so do only
vapour presure=molecular weight of water/2
=18/2
=6

Answer 28

as formular of water dosent change in any state -_-

Answer 29

18/2=9

Answer 30

@heena

Answer 31

sorry yea 9 ^.^

Answer 32

so next

Answer 33

nooooooooooooooooo u never do qn by urself :/ now allong with ur qn show us ur attempt also -_-

Answer 34

i want u to tell wat should i do i will solve it

Answer 35

ok

Answer 36

then plzz tell

Answer 37

@heena

Answer 38

wat ? i guess for this we already shown u formula ...

Answer 39

what means for the same qn or other qn u are going to give us?

Answer 40

@heena can you please send me a link on the formula you've used above - (molecular weight/2) for vapour pressure? I've been looking for it on the net but I can't get a grip on it. Thanks :)