What famous Pythagorean triple has values G, 21, and 29?
A Pythagorean triplet is in form a,b,c where \(a^2 + b^2 = c^2\)
So, \(g^2 + 21^2 = 29^2\) Just solve for g.
a^2+441=841 Subtract 441 on both sides and get sqrt"400". Once you do the square root of both sides, it becomes a=20.
LOL, Im an old guy who has forgotten his math,,,,how do I solve for g
21^2 = 441 29^2 = 841. \( \color{Black}{\Rightarrow g^2 + 441 = 841 }\) \( \color{Black}{\Rightarrow g^2 = 400}\) \( \color{Black}{\Rightarrow g = \sqrt{400}}\) 400 is a perfect square I believe ^_^
Yep, it goes down to 20.
Exactly. :D
I'm lost, I'm sorry so g=400?
No..
\( \color{Black}{\Rightarrow g^2 = 400 }\) If you find the square root of both sides: \( \color{Black}{\Rightarrow g = \sqrt{4000} }\)
\(g = \sqrt{400}\) correction
so g is the square root of 400
Yeah, but square root of 400 is an integer :)
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