Question

a stone attached on a rope. That stone performs a uniform circular motion with a radius of 1 ~ m The stone makes one revolution per second. The average acceleration of the stone during 1/4 revolution is?

Answer 1

@experimentX (:

Answer 2

i hope it's horizontal

Answer 3

the centripetal acceleration is \( \large \frac{v^2}{r}\) and it is constant since your angular velocity is constant

Answer 4

v - linear velocity
\( \omega \) - angular velocity
r - radius
----------------------
\( v =\omega r\)
----------------------
and
\[ \omega = \frac{2\pi}{T}\]
T is time period, and in your case 1

Answer 5

using above relation find v^2/r

Answer 6

or simply \( \omega^2 r\)

Answer 7

thank you!^^

Answer 8

yw