Question

Find the area of a circle whose area equals the half of the sum of the areas of two circles with radii 2 and 3.
the way this is written is confusing me can someone please explain it to me

Answer 1

i want to learn and me just getting the answer off the internet wont help me at all

Answer 2

thank you for the quick response

Answer 3

I put it in more "mathematical "notation, :)
"A" will be the area you looking for. The circle are formula is: Pi*r^2. So.....
A=1/2(Pi*2^2+Pi*3^2)

Ok?

Answer 4

ok give me ona momenta to solve

Answer 5

radii is the radius right :/

Answer 6

yes

Answer 7

thanks

Answer 8

12.5 pie?

Answer 9

The area of the first circle (with a radius of 2) is

A = pi*r^2

A = pi*2^2

A = pi*4

A = 4pi

The area of the second circle (with a radius of 3) is

A = pi*r^2

A = pi*3^2

A = pi*9

A = 9pi

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The sum of the two areas is just the result of adding the two areas up. So

Sum of two areas = (Area 1) + (Area 2)

Sum of two areas = 4pi + 9pi

Sum of two areas = 13pi


Now take half of this sum to get


13pi/2 = 6.5pi

Answer 10

A=1/2(Pi*2^2+Pi*3^2) = 1/2(13*Pi)

Answer 11

ohh! ok i see so i used 4 not 2 thank you both!!

Answer 12

yw