find the exact value of sin2π/3
0.8660254038
sqrt3/2
wat answer do u want
find the coordinates of the point on the unit circle corresponding to the angle \(\frac{2\pi}{3}\) on the last page of the attached cheat sheet. the first coordinate is \(\cos(\frac{2\pi}{3}) \)the second coordinate is \(\sin(\frac{2\pi}{3})\)
\[\pi/3=60^0\]do you know the exact values of \(\sin(60)\) and \(\cos(60)\)? if you do then you can use the identity:\[\sin(2x)=2\sin(x)\cos(x)\]to work this out.
too much work
k sir
you can also use the identity:\[\sin(x)=\sin(\pi-x)\]to get:\[\sin(2\pi/3)=\sin(\pi-2\pi/3)=\sin(\pi/3)\]
but why \[\sin(x)=\sin(\pi-x)\] It is becoz u should know that in 2nd quadrant sine is (+)ve.
yes you can do either of those things, but it is really easier to locate \(\frac{2\pi}{3}\) on the unit circle and read off the coordinates
yes @satellite73 sir are correct even my words lie on the unit circle:)
Join our real-time social learning platform and learn together with your friends!