Question

2^(-6x)=15^(x-3)
Solve for x .


Write the exact answer using base-10 logarithms.

Answer 1

ok actually it is
\[-6x\log(2)=(x-3)\log(5)\]

Answer 2

multiply out on the left get
\[-6x\log(2)=x\log(5)-3\log(5)\] then
\[x\log(5)+6x\log(2)=3\log(5)\]
\[x\left(\log(5)+6\log(2)\right)=3\log(5)\]
\[x=\frac{3\log(5)}{\log(5)+6\log(2)}\]

Answer 3

thats the right answer

Answer 4

except everywhere i wrote a 5, you should write a 15

Answer 5

satellite can you come help me please!!!!!!!!!! after this