Question

Factor: xy-2y-x+2

Answer 1

divide this in 2 terms ::
1) \(\huge{xy-2y}\)
2) \(\huge{-x+2}\)

Answer 2

That's all?

Answer 3

try to simplify first term .. by taking y common

Answer 4

what do you get?

Answer 5

y(x-2)

Answer 6

great ..
now in 2nd equation what we have .... \(\huge{-x+2}\)
take (-) common from 2nd equation ... what you get?

Answer 7

-x+2?

Answer 8

nope ... when you take (-) common you will do like this :

first write -x+2 as \(\huge{-(x)-(-2)}\) as -(-x) = +x
now take (-) common.... what you get now ? :

\(\huge{-(x+(-2))}\)
\(\huge{-(x-2)}\)

Answer 9

Now combine both simplified terms. ..

1) y(x-2)
2) -(x-2)

Answer 10

what you get ? it should be like this :

\[\huge{y(x-2)-(x-2)}\]
\[\huge{(x-2)(y-1)}\]

Answer 11

that is the answer to your question ... did u get that ?

Answer 12

You don't have to square x-2?

Answer 13

no .. we took (x-2) common
that means (x-2)(y-1)

Answer 14

according to the inverse rule of distributive property :

ab+ac = a(b+c)