Question

Simplify. √72x^5y^4

Answer 1

\[\sqrt{72x^5y^4}\]

Answer 2

^^^ there it is f you can't read it

Answer 3

start with the fact that \(72=2^3\times3^2\) and write this as
\[\sqrt{2^3\times 3^2\times x^5y^4}\] and then we can finish easily
you are taking the square root.
the exponent on the 2 inside the radical is 3, two goes in to 3 once, with a remainder of 1, so one two comes out, one says in
the exponent on the 3 is 2, and 2 goes in to 2 once, the 3 comes out
the exponent on the \(x\) is 5, 2 goes in to 5 twice with a remainder of 1, so \(x^2\) comes out and \(x\) stays in
and finally the exponent on the \(y\) is 4, and two goes in to 4 twice, \(y^2\) comes out
it looks long written this way, but in fact this is the way you do it in your head
that gives an answer of
\[2\times 3\times x^2\times y^2\sqrt{2x}\] or
\[6x^2y^2\sqrt{2x}\]

Answer 4

thanks

Answer 5

btw i hope it is clear that using notation i could have written an answer very quickly, but this is what you should be thinking in your head when you do it and then you can finish almost instantly
yw