Question

How do you factor this..?

Answer 1

\[a ^{6}+b ^{3}\]

Answer 2

try expressing it as \[\huge a^6 + b^3 = (a^2)^3 + b^3\] sum of two cubes ;)

Answer 3

\[\huge x^3 + y^3 \implies (x+y)(x^2 - xy + y^2)\]
just a reminder ^_^

Answer 4

get it now @sakigirl ?

Answer 5

Still a bit confused.

Answer 6

think of a^2 as x

and b as y

Answer 7

\[\huge{a^6+b^3 = (a^2)^3 + b^3}\]

Remember a rule : \(\huge{(a^b)^c = a^{(bc )}}\) applying the inverse we did the above factor question

Answer 8

then transform it into the form (x+y)(x^2 - xy + y^2)

Answer 9

@lgbasallote is right .... just make it easy ... think of x which is equal to \(a^2\)

\(\huge{x^3 + b^3 = (x+b)(x^2-xb+b^2)}\)

Answer 10

now put the value of x in this equation

Answer 11

What do you get ?