Question

simplify the following quotient of complex numbers into the form a + bi
-i/8+8i

Answer 1

The form a + bi is
\[0+i(8-\frac{1}{8})\]
Now you can simplify it.

Answer 2

multiply top and bottom by 8-8i:
-i(8-8i) / (8+8i)(8-8i)=-8-8i /64 +64 = -8-8i /128 =(-1-i)/16

Answer 3

In form of a + ib :
= 8i - i/8

Taking i common:

= i(8 - 1/8)
Solving it further by taking LCM : i(64 - 1)/8

= 63i/8..

Also, it can be written as : 0 + 63i/8

Comparing it with (a + ib),

a = 0 and b = 63/8..

So, in (a + ib) form : It is 0 + 63i/8 or simply 63i/8...