If sin x = .21,what is cos x?
Use this : \[\sin^2x + \cos^2x = 1\]
Or in simpler way : \[cosx = \sqrt{(1 - \sin^2x)}\]
Because there are two values of x will give you a value of 0.21 there will be two solutions to this question. To find the first value we can directly solve the angle using:\[\sin x =0.21\]\[ x = \sin^{-1}{(0.21)} \]\[x= 12.1222^o\] now we can obtain the first solution through direct substitution: \[\cos x_1 = \cos(12.1222^o)\] \[\cos x_1 = 0.9777\] the second angle comes from the cast diagram and utilizes the first angle you solved. the attached picture shows how to solve the second angle that satisfies sinx = 0.21. substitute this angle into cosx to obtain your second solution: \[\cos x_2 = \cos(167.87^o)\] \[\cos x_2 = -0.9777\] As it turns out, theses arre the same solutions you get through @waterineyes 's method when considering that roots usually contain a positive and negative pair
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