PLEASE HELP ME SOMEONE :(( thats good in geometry!

Question

terenzreignz · Answer

But what's the question?

anonymous · Answer

In △JKL, solve for x. 



 17.32 

 38.16 

 66.73 

 74.89

maheshmeghwal9 · Answer

Since; $$\tan \theta =\frac{perpendicular}{hypotenuse}.$$Therfore; $$\tan 27^o=\frac{34}{x}.$$& $$\tan 27^o=0.509$$So now find 'x': -
$$\huge{\color{red}{☺}}$$

maheshmeghwal9 · Answer

$$\color{blue}{x=\frac{34}{0.509}=?}$$

anonymous · Answer

i dont know how to!

amistre64 · Answer

tan doesnt play with hypots; only legs.  but you did get the right values for it

maheshmeghwal9 · Answer

sorry ya it is base @amistre64

maheshmeghwal9 · Answer

a typing mistake really sorry

anonymous · Answer

whats the answer?

amistre64 · Answer

Emma, use a calculator to finalize the results

anonymous · Answer

this is why i am asking you guys. because i really dont know how.

maheshmeghwal9 · Answer

u need a gr8 guide:)

amistre64 · Answer

your asking for "the answer".  and that is not appropriate in this forum.  we are here to guide you

anonymous · Answer

i dont understnad

amistre64 · Answer

you need to know the definition of the trig functions then.

amistre64 · Answer

the tangent function applies to this problem, since its parts are defined as the tangent function.

terenzreignz · Answer

@Emmalaylay_Love101 Have you gotten it yet?

anonymous · Answer

noo
 :(

terenzreignz · Answer

Oh, well, if you like, I can take you through it step by step, but try to figure it out on your own

anonymous · Answer

this test os timing me. could u guys please just give me the answer?

maheshmeghwal9 · Answer

$$x \approx 68.$$So u can take it as
x=68.