Ask your own question, for FREE!
Mathematics 76 Online
OpenStudy (anonymous):

Find the limit (medal given for showing steps!): \[\huge \lim_{x \rightarrow 1} \frac{5x}{x-1} - \frac{5}{ln x} \] (I keep getting -∞ even after the derivation)

OpenStudy (experimentx):

\[ \infty - \infty \text{ case, i can be changed into } 0/0 \text{ case if you manipulate it carefully. }\]

OpenStudy (experimentx):

*it

OpenStudy (experimentx):

\[ \huge \frac{5x}{x-1} - \frac{5}{\ln x} = \frac{5x \ln x - 5(x-1)}{(x-1)\ln x} \] Now use L'hopital's rule

OpenStudy (anonymous):

Yes, Agentx, I think this is a case of not being careful enough in applying L'Hopital's rule. To use L'H's, it is required that our limit be of one of these indeterminate forms: \[\large \frac{0}{0}, \frac{\infty}{\infty}, \frac{-\infty}{-\infty}\] With your problem, if you evaluate at 1, you get \[\large \frac{5}{0}-\frac{5}{0}\] And you can't use L'Hopital's on either of those forms.

OpenStudy (anonymous):

However, as experiment shows, you can manipulate these a bit so that they are in indeterminate form. =D

OpenStudy (anonymous):

Thanks to you both! :D

OpenStudy (anonymous):

My pleasure! =D

OpenStudy (experimentx):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Midnight97: Can I get some help because I forgot how to do this
22 minutes ago 5 Replies 2 Medals
YouMyPlug: A lil sum sum
25 minutes ago 20 Replies 5 Medals
SnowKitty: Can I get some help please
3 hours ago 7 Replies 2 Medals
Coyote: Trigonometry
3 hours ago 3 Replies 2 Medals
Thayes: Listen
5 hours ago 5 Replies 1 Medal
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!