Question

Need help with this one!!! A panel of judges must consist of four women and three men. A list of potential judges includes six women and five men. How many different panels could be created from this list?

Answer 1

(6 women + 5 men) = 11 ppl to choose from, (4 women + 3 men) = 7 ppl chosen

This is a combination, order doesn't matter. Otherwise it would be a permutation (sp?).

I think...

Men : 5 nCr 3 = 10
Women : 6 nCr 4 = 15

Sum the two for 25 combinations total?

Can somebody please check me on this?

I don't really feel confident this is necessarily the answer, sorry. :-/

Answer 2

the posible answers for this question are
a) 30
b) 150
c)216
so 25 is not the answer :/ but thanks for trying!

Answer 3

Thanks @palomamtz15 all I recalled was this forumula:
\[\frac{n!}{(n-r)!}\]
where n is the number of things to choose from, and you choose r of them

and this fact:
If the order doesn't matter, it is a Combination.
If the order does matter it is a Permutation.

Answer 4

10*15 = 150 = answer?

Answer 5

o_O

Answer 6

THAT was the ANSWER!! Thanks a lot! :D

Answer 7

Ah I see...

That's the permutation formula above, the combination formula is:
\[ nCr = \frac{n!}{r!(n-r)!} \]
\[ nCr = \frac{5!}{3!(5-3)!} = 10\]

Answer 8

And there's the math that is going on in my calculator :P

Answer 9

:) thanks for the help! I really need that answer!

Answer 10

5! = 1*2*3*4*5 = 120

Answer 11

needed*