If it takes Dave 11 hours to close an order and John needs 13 hours how long would it take them together
13 + 11 ÷ 2
oops
\[\frac{11\times 13}{11+13}\]
Really? I'd have thought if they were working together, the answer should be less than if they were working alone
D: I'm a retard... Okay so @Satellite73 can you explain this to me haha...I should be failing my own math right now...but somehow I am not. o.O
"close an order" is not really that clear to me, but i am assuming it is one of those problems like "adam takes 13 hours to mow the lawn and eve takes 11 hours. how long would it take for them to paint the room if they work together?"
@rebeccaskell94 the combined rate is not the average of the two rates
This I see haha
dave's rate is \(\frac{1}{11}\) and john's rate is \(\frac{1}{13}\) so their combined rate is \(\frac{1}{11}+\frac{1}{13}=\frac{11+13}{11\times 13}\)
OHHHH!!!! duh. http://viewfromthedolequeue.files.wordpress.com/2011/04/dunce_cap.jpg <---moi
then you want how long it takes to complete one job, set \[\frac{11+13}{11\times 13}T=1\] solve via \[t=\frac{11\times 13}{11+13}\]
of course you still have to compute, i just wrote what you need to compute
okay! Thank you so much. I shall do my best to remember :D
you can recreate if for yourself each time, but if you do more than a couple of these you can go right to the answer
Awesome! Thanks!
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