Question

can you please help!!!!!!!!! (v+1) (v2-v+1) the 2 is an exponent

Answer 1

seems like you have a sum of cubes, what do you need help with?

Answer 2

Hint: (v+1)(v^2-v+1) = v(v^2-v+1) + 1(v^2-v+1)

Answer 3

how do you solve it and what is the problem even called. My teacher does not help at all

Answer 4

What happens when you distribute v(v^2-v+1) ?

Answer 5

you multiply them?

Answer 6

yes, v*v^2 - v*v + v*1

Answer 7

so whats the answer?

Answer 8

tell me what you get and I'll confirm it for you

Answer 9

ahh i dont know.... you do V times v2?

Answer 10

yes, which gives you what?

Answer 11

v3-v2+v?

Answer 12

you got it

Answer 13

that's just part of the answer though

Answer 14

Now distribute 1(v^2-v+1)

Answer 15

v2-v+1?

Answer 16

you got it

Answer 17

so

v(v^2-v+1) + 1(v^2-v+1)

becomes

v^3 - v^2 + v + v^2 - v + 1

Answer 18

To finish off, combine like terms

Answer 19

v3-v2+v
v2-v +1 answer: v3+v+1?

Answer 20

close

Answer 21

notice we have a +v and a -v

Answer 22

so its a -v

Answer 23

what is v-v ?

Answer 24

0

Answer 25

yes, so the v terms basically go away

Answer 26

so v3+1 is the answer?

Answer 27

yes

Answer 28

thank you soooooooo much!!!!!!!!!!!!!!

Answer 29

you're welcome