express as a single fraction the exact value of sin 75
sin75=sin(45+30)
sin 75 = sin(45 + 30) = sin 45 cos 30 + cos 45 sin 30 Can you simplify from here?
yupp thanks!
You're welcome :)
We got \(\sin 45 \cos 30+ \sin30 \cos45\) \(\sin(30) = \frac{1}{2} \) \(\sin(45) = \sqrt{\frac{1}{2}} \) \(\cos(30) = \sqrt{\frac{3}{4}}\) \(\cos(45) = \sqrt{\frac{1}{2}}\) \(\large \begin{align} \ &=\sin 45 \cos 30+ \sin30 \cos45\\ \\ &= \sqrt{\frac{1}{2}} \sqrt{\frac{3}{4}}+\frac{1}{2}\sqrt{\frac{1}{2}}\\ &= \sqrt{\frac{1}{2}*\frac{3}{4}} + \frac{1}{2}\sqrt{\frac{1}{2}}\\ &= \sqrt{\frac{3}{8}}+ \frac{1}{2}\sqrt{\frac{1}{2}}\\ \end{align}\) \(\large \begin{align} \ &= \frac{\sqrt{24}}{8}+\frac{1}{2}*\frac{\sqrt{2}}{2} \\ &= \frac{\sqrt{24}}{8}+\frac{\sqrt{2}}{4} \\ &= \frac{\sqrt{24}}{8}+\frac{2\sqrt{2}}{8} \\ &= \frac{2\sqrt{2}+\sqrt{4*6}}{8} \\ &= \frac{2\sqrt{2}+2\sqrt{6}}{8} \\ &= \frac{\sqrt{2}+\sqrt{6}}{4} \\ \end{align}\)
thank you! very clear response :)
Uhh... @zepp \[\sin(30) = \frac12\]\[\sin(45) = \frac{\sqrt{2}}{2}\]\[\cos(30) = \frac{\sqrt{3}}{2}\]\[\cos(45) = \frac{\sqrt{2}}{2}\]
Yeah, when you rationalize it.
Oh ok. Sorry. I didn't realize that. :)
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