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Mathematics 17 Online
OpenStudy (anonymous):

Rewrite the expression tanA (tanA + cotA) in terms of a single trigonometric ratio.... I have never added the identities before so I'm not sure what to do next. I have already converted all of the trigonometric functions to sine and cosine functions, but just don't know what to do next :/

terenzreignz (terenzreignz):

Well, well, we meet again ;) What do you mean by 'single trigonometric ratio' do you mean just one function (sin, cos, tan, etc) ?

OpenStudy (anonymous):

Lol yes indeed (: And yes, it's asking that I simplify this expression into just one function

terenzreignz (terenzreignz):

Ok, is tanA being distributed?

OpenStudy (anonymous):

Yes because it's on the outside of the parenthesis, right?

terenzreignz (terenzreignz):

ok, then distribute it ;)

OpenStudy (anonymous):

Alright, I know that the first distribution make tanA = tan^2 A, but what about cotA? It's not the same function so do I just place it next to cot A like multiplication?

terenzreignz (terenzreignz):

haha, but what about the *ehem* 'special' relationship between tan and cot... look within yourself :D

OpenStudy (anonymous):

Lol special relationship? I never learned about that (:

terenzreignz (terenzreignz):

well, you know that tan = sin/cos, right? What's cot?

OpenStudy (anonymous):

I know they're just the reciprocal of each other

terenzreignz (terenzreignz):

so, if they're reciprocals, then their product is...?

OpenStudy (anonymous):

cos/sin

OpenStudy (anonymous):

It is...tangent? D: I'm sorry I'm a little lost. Taking a shot in the dark

terenzreignz (terenzreignz):

haha, cos/sin * sin/cos = cos sin/ sin cos which is just...?

OpenStudy (anonymous):

cot/tan? :o

terenzreignz (terenzreignz):

remember some of the more fundamental identities: sin * csc = 1 cos * sec = 1 tan * cot = 1

OpenStudy (anonymous):

ohhh, durr. That was right in front of me -_- Lol

terenzreignz (terenzreignz):

so, we've reduced the entire shebang to tan^2 A + 1 Can you do it from here?

OpenStudy (anonymous):

Would it be sec^2 A? (:

terenzreignz (terenzreignz):

That is correct, and that, I believe, is what you were going for?

OpenStudy (anonymous):

Yes! Thank you :D

terenzreignz (terenzreignz):

No problem

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