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[6.05] An airplane flew 3 hours with a 40 mph head wind. The return trip with a tail wind of the same speed took 2 hours. Find the speed of the plane in still air. 180 mph 200 mph 220 mph 240 mph
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is the answer 240?
Let s = still air speed of plane Distance traveled on outward trip = (s - 40) * 3 = d Distance traveled on return trip = (s + 40) * 2 = d 3(s - 40) = 2(s + 40) 3s - 120 = 2s + 80 Can you solve for s ?
yes and i got 40 as my answer
3s - 120 = 2s + 80 Subtract 2s from each side (3s - 2s) -120 = (2s - 2s) + 80 s -120 = 0 + 80 Add 120 to each side s - (120 +120) = 80 + 120 s = 80 + 120 = ? mph
200
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200 mph is the correct choice.
thanks :)
You're welcome :)
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