compute lim x^2+3x-10/ x-2 x-->2 How would I compute this limit?
First step: Factor the polynomial in the numerator of the fraction.
lol can you explain how to do that?
You should have learned factoring polynomials a long, long time before ever learning limits. I would recommend practicing factoring polynomials on Khan Academy for a while until you are very comfortable with it. In this case, you want to look for two numbers that multiply to -10 and sum to 3. The numbers in this example will be 5 and -2. So, you can factor the polynomial into (x+5)(x-2). The (x-2) terms then cancel, and you're left with \[\lim_{x\to2}x+5\]
ohhhhhh ok i know how to that hold on let me try to work it
ok i got 7
Yes, that is the correct answer. Again, though, you should go get comfortable with factoring polynomials before you try to go any further with limits.
no no im good with them i really know how to do that i just didn't know what it was called
but I have one more question for you are you good with derivatives? i understand them but this has me confused
y=e^9x^3+4x
\[y=e^{9x ^{3}+4x}\]
Just use the chain rule :)
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