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determine the derivative with respect to x of y=e^9x^3+4x
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\[y=e ^{9x ^{3}+4x}\]
You need to apply the chain rule, you have the function 9x^3+4x "inside" the function e^x. So you need to apply this rule: \[\frac{d}{dx}f(g(x))=f'(g(x))*g'(x)\] Here: \[f(x)=e^x; g(x)=9x^3+4x \implies f'(x)=e^x \implies f'(g(x))=e^{9x^3+4x}; \] \[g'(x)=27x^2+4; \implies \frac{d}{dx}e^{9x^3+4x}=(27x^2+4)e^{9x^3+4x}\]
Also note: \[f(x)=e^x; g(x)=9x^3+4x \implies f(g(x))=e^{9x^3+4x} \] Which is your function which is why this rule is applied and works.
ok im with you i was confused but i just got it lol thanks
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