Question

Solve the equation for y. Then find the value of y for the given value of x.
3/5y-4x=3-2y; x=9

Answer 1

What is it that you don't understand?

Answer 2

So you plug in the value of X and then you solve it.

\[3/5y-36=3-2y\]
\[13/5y=39 \]\[Multiply 5 \to each side\]
\[13y=195\]
\[y=195/13\]
\[y = 15\]

Answer 3

Yup :). But I don't see what you did on your 2nd line... I really don't understand how you got that answer am getting something completely different your question is...
\[\frac{3}{5y}-4x=3-2y\] right?

Answer 4

It ends up being a quadratic that has to be solved using the quadratic formula.

Answer 5

Thanks!

Answer 6

\[\frac{3}{5y}-4(9)=3-2y\]
\[\frac{3}{5y}-36=3-2y\]
Add 36 to both sides
\[\frac{3}{5y}=39-2y\]
Multiply both sides by 5y
\[3=(39-2y)5y\]
\[3=195y-10y^2\]
Put the equation in standard form
\[0=-10y^2+195y-3\]

Answer 7

You do know how to use the quadratic formula right?

Answer 8

Yeah

Answer 9

Okay let me know if you have any problems! and You're welcome