OK I FOUND A MISTAKE IN THE PH (ACID-BASE) METER SCIENTISTS INVENTED!!!

Question

anonymous · Answer

ok lets say i have 1L of water, and I ONLY PUTS 10^-9 mol of NaOH, well, this gives a pH of 5, but i mean WHHHHAAAATTT, how can it be acid if i put only base?? HELP PLZ??

anonymous · Answer

sorry if i post in this section, because 1) no one is in chem, and 2) i believe this is mathematically related

unklerhaukus · Answer

the $H_2O$ will break into
$$H^++OH^-$$

anonymous · Answer

Generally, you don't find mistakes in things which have been around for decades and have been reviewed and used by millions of scientists around the world.

Just sayin'.

anonymous · Answer

I NEED AN EXPLANATION PLZ

unklerhaukus · Answer

how did you get a pH of 5?

anonymous · Answer

@UnkleRhaukus
we have 10^-9 mol of OH in 1L, hence [OH-] = 10^-9 
pOH = -log[OH-]
pOH = -log[10^-9] 
pOH = 9

pOH + pH = 14
pH = 5

anonymous · Answer

trust me this calculation isn't wrong, my several nerd friends are also mind-fk'ed when they realized this...

unklerhaukus · Answer

well you must have made a false assumption

unklerhaukus · Answer

$${H_2O}_{(l)}+{H_2O}_{(l)}\Longleftrightarrow {H_3O^+}_{(aq)}+{OH^-}_{(aq)}$$
$${H_2O}_{(l)}+{H_2O}_{(l)}\Longleftrightarrow +H^+_{(aq)}+{OH^-}_{(aq)}$$

unklerhaukus · Answer

see what the chemistry department has to say remember this is a chemistry problem not simply a math problem http://openstudy.com/study#/groups/Chemistry