Question

Whats the equation of the asymptotes for the hyperbola ((y+4)^2)/(36)-((x-3)^2)/(25) If anyone can understand it?

Answer 1

This should be your equation
\[
\frac{(y+4)^2}{36} -\frac {(x-3)^2}{25}=1
\]

Answer 2

To find the asymptotes you put replace the minus sing by = sign and you take away the 1.
Near Infinity 1 is almost nothing.
\[
\frac{(y+4)^2}{36} =\frac {(x-3)^2}{25} \\
\frac{(y+4) }{6} =\pm\frac {(x-3)}{5} \\
y-4 =\pm\frac 6 5{(x-3)}\\
y =4\pm\frac 6 5{(x-3)}
\]