Question

If a sample of HNO3 is found to contain 6.74 · 1024 N atoms how many moles of H atoms are present?

Answer 1

Molar Mass (g/mol)
HNO3 63.013
N atom 14.007
H atom 1.0080
O atom 15.999
Avogadro's No. (mol-1)
6.022×1023

Answer 2

In HNO3, number of H atoms = number of N atoms

number of moles of H =
\[\frac{number of\ H\ atoms}{Avagadro\ number}\]

\[ =\frac{6.74 * 10^{24}}{6.022 * 10^{23}}\]
= 11.2 moles