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Mathematics 13 Online
OpenStudy (anonymous):

Find k so that the following function is continuous on any interval: f(x)=kx if 0<=x<3 and f(x)=8x^2 if 3<=x K=?

OpenStudy (anonymous):

for x=3, the right piece of the function has value 72.. so to make this continuous, the left piece must have a value of 72 also... so, kx = 72 k(3) = 72 can you take it from here?

OpenStudy (anonymous):

yup thanks

OpenStudy (anonymous):

yw...:)

OpenStudy (anonymous):

wait im lost plz continue ?

OpenStudy (anonymous):

3k = 72 divide both sides by 3....

OpenStudy (anonymous):

where did u get 3k?

OpenStudy (anonymous):

k(3) = 72 from the last post i made before i came back..

OpenStudy (anonymous):

ok thanks now i got it

OpenStudy (anonymous):

ok...

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