Question

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Answer 1

@coolaidd Do you want to learn or prefer guessing forever?

Answer 2

Remember that x^2+y^2=radius^2
Here the radius is 1 and 1^2=1
The center is is up 3 units, so you have (y-3)^2
\[x ^{2}+(y-3)^{2}=1\]

Answer 3

(x-0)^2+(y-3)^2=1^2
x^2+(y-3)^2=1

Answer 4

@brainshot3, have you read the CoC?
http://openstudy.com/code-of-conduct
We're here to help others learn, not simply post answers. Since this is a fairly elementary question, I believe this could be taught to coolaidd rather than simply telling her.

Answer 5

A

Answer 6

normally s circle with centre at (0,0)
the equation is x^2+y^2=1

Answer 7

here the origin is shifted to (0,3)
so the equation is (x-0)^2+(y-3)^2=1

Answer 8

so mam got it?

Answer 9

thanks! :)

Answer 10

youre welcome
any other help required?